x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
X3 + 8= (x+2)(x2-2x+4)
x2 + 6x + 8 =(x + 2)(x +4)
Find factors of 8 that add up to 6. (x + 2)(x + 4)
(x + 7)(x + 8)
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
(x + 2)(x^2+4)
y5(x3 - 8)
If that's 2x2, the answer is (x + 2)(x2 + 4)
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
(2x - 1)(x + 2)(x^2 - 2x + 4)
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes
x2(x - 8)
2x3 + 16 = 2(x3 + 8) = 2(x3 + 23) = 2(x + 2)(x2 - 2x + 22) = 2(x + 2)(x2 - 2x + 4)
(x+2)(x2+2x+4)
(x - 8)(x2 + 8x + 64)