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You don't, if you're only looking for real number results. If you are including imaginary numbers, x2+4 = (x+2i)*(x-2i).
Wiki User
∙ 13y ago
Wiki User
∙ 13y agoTake out the common factor, "x". If you divide each term by "x", you get the other factor.
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How do you factor this polynomial completely four x squared plus four x minus three?
(2x - 1)(2x + 3)
Factor x squared y squared plus ay squared plus ab plus bx squared?
(a + x^2)(b + y^2)
Can you factor x squared plus 4x plus 2?
No
How do you factor x cubed plus 9x squared plus 2x plus 18?
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Factor X squared y plus axy plus abx plus a squared b?
x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)
Factor x squared plus 5x plus 4?
(x+1)(x+4)
How do you factor x squared plus 3x plus 2?
(x + 2)(x + 1)
How do you factor x squared plus 9x plus 8?
(x+1)(x+8)
How do you factor x squared plus 6x plus 9?
(x + 3)(x + 3)
Factor x squared plus 5x plus 6?
(x + 3)(x + 2)
How do you factor x squared minus 12 x plus 36?
x squared minus 12 x plus 36 = (x - 6)(x - 6)
Factor 4x squared plus 8xy plus 4y squared?
4(x+y)^2
