(x + 2)(x + 1)
3x^2 -14x +15 = (3x-5)(x-3)
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
(x + 2)(3x - 1)(3x + 1)
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
It is a quadratic expression and can be factored into: (3x+1)(x+2)
(3x - y+ 2)(3x + y + 2)
(3x - 2)(x + 8)
(3x + 3y)(x + y) = 3(x + y)2
-1
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
3x^2 -14x +15 = (3x-5)(x-3)
(x^2 - 3x + 5)(x^2 + 3x + 5)
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
2(5x - 1)(3x - 2)
(x + 2)(3x - 1)(3x + 1)
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
(x - 2)(2x + 7)