x2 - 9x + 8 = (x-1)(x-8)
x2-9x+8=0 has two solutions:x = 8x = 1
(9x + 8)(9x - 8)
It is (x-1)(x-8) when factored
(x + 8)(x + 1)
x2 - 9x + 8 = (x-1)(x-8)
x2-9x+8=0 has two solutions:x = 8x = 1
the answer is (3x-2)(9x squared+6x+4)
Integral : 9x + 8 = 9(x squared)/2 + 8x Differential : 9x +8 = 9
(9x + 8)(9x - 8)
(3x + 8)(3x - 8)
-9(x + 8)
It is (x-1)(x-8) when factored
(x + 8)(x + 1)
(x-9)(x+9)
(9x - 8)(5x + 7)
(x + 8)(x + 1)