It's hard to write this on a typewriter keyboard. Do you mean
xb + (1-x)b , or xb + 1 - xb , or maybe even x(b+1) - xb ?
The first cannot be factored.
The second equals 1, so it is already prime (cannot be factored).
The third could be written as xb(x) - xb(1), so there is a common factor of xb, and the expression can be factored as
xb(x-1). This is prime.
(2x - 1)(x + 4)
1
(7a - 1)(6a + 1)
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
There is no rational factorisation.
(5w + 1)(w + 1)
Factor it. y(4y - 1)(3y - 2) = 0 y = 0, 1/4, 2/3
(x + 2)(3x - 1)(3x + 1)
1.plus 2.minus 3.multiplied by 4.divided by
(3x - 1)(2x - 7)
(4n - 1)(3n + 2)
(x2 plus 40) (x minus 1)