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How do you factor x squared minus y squared?
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
How do you factor x squared minus y squared minus four?
x^2 - y^2 - 4 is in its simplest form.
When you completely factor 3x2 y what do you get?
3 * x * x * y
How do you factor 16a2 4b2?
Assuming the missing sign is "minus" then you have the difference between two squares. This is solved as (x + y)(x - y). In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
How do you factor this x raised to the power of 8 y raised to the power of 8?
x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
How do you factor x2 minus y2?
(x - y)(x + y)
How do you factor x squared minus 2 x y plus y squared?
it is (x-y)(x-y) :)
How do you factor completely x square minus y squared?
(x - y)(x + y)
How do you factor x squared minus y squared?
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
How do you factor 64 x cubed minus y cubed?
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
How do you completely factor x to the fourth power minus y to the fourth power?
It is: (x-y)4
How do you factor x squared minus y squared minus four?
x^2 - y^2 - 4 is in its simplest form.
How do you factor x squared minus four y squared minus twenty eight?
There are no rational factors.
How do you factor out completely x squared y minus y cubed?
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
How minus times minus is plus?
Let y= ab+(- a)(b) +(-a)(-b) factor out -a y= ab+(-a){b+(-b)} y=ab+(-a)(0) y =ab -------------------(1) now factor out b y= b{a+(-a)}+(-a)(-b) y= b(0) +(-a)(-b) y= (-a)(-b)-----------------(2) equate (1) and (2) (-a)(-b)=ab minus x minus = positive
How do you factor the perfect-square trinomial in y (x2 plus 2x plus 1) and minus 1 and minus 1. y (x plus )2 and minus 1 and minus1?
To factor the perfect square trinomial (y(x^2 + 2x + 1) - 1 - 1), first notice that (x^2 + 2x + 1) can be rewritten as ((x + 1)^2). Therefore, the expression simplifies to (y((x + 1)^2) - 2). This can be expressed as (y(x + 1)^2 - 2).
How do you factor Y squared minus y minus 6?
y² - y - 6 = (y + 2)(y - 3)
