Assuming the missing sign is "minus" then you have the difference between two squares.
This is solved as (x + y)(x - y).
In your example x = 4a and y = 2b so the factorisation is (4a + 2b)(4a - 2b) or more completely: (4)(2a + b)(2a - b).
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4(4a2 - b2) 4(2a + b)(2a - b)
4(16a4 + b2)
Not sure about the greatest commom factor, but the greatest common factor is b.
GCF(28a5, 16a2) = 4a2.
a proper factor is a factor.