(2n+3)(n+1)=2n2+5n+3.
It is: 3(t+3)
N=3.
-2n
5n + 3 = 14 - 6n <=> 5n +6n = 14 - 3 <=> 11n = 11 => n = 11/11 = 1
It is 3a(a+3) when factored
It is: 6(4x+3)
It is: 3(x+2)
(x+5)(x+3)
5N + 3 Just add the Ns and put +3 on the end!
It is 3(2y+5) when factorised
(5x + 2)(x + 3)
Subract 5n from both sides and you get 9=-3n, then divide bother sides by -3 and you get n= -3