-4n3 + 8n2 - 4n + 7
10, 48 and 116. These are derived using the cubic generator: Un = (-4n3 + 27n2 - 47n + 30)/3 for n = 1, 2, 3, ...
The answer depends on which number is missing. Even if the location of the gap is know, there are infinitely many possible solutions. The solutions listed below are polynomials of the lowest degree. First: 5 using the rule Un = (-4n3 + 48n2 - 128n + 99)/3 Second: 0 using the rule Un = (-7n3 + 84n2 - 209n + 138)/6 Third: 21.666 (recurring) using the rule Un = (3n3 - 23n2 + 84n - 61)/3 Fourth: 50 using the rule Un = (-11n3 + 90n2 - 121n + 48)/6 Fifth: 65 using the rule Un = (-4n3 + 36n2 - 44n + 15)/3
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
It is 77
-4n3 + 8n2 - 4n + 7
4n3 - 12n2 - 7n + 9
the cheat to find giratina is WNWY JXTK &5C1 4N3- P4NM 8K&C
One possible solution is t(n)= [-4n3 + 21n2 - 16n + 18]/3
you beat him twice at World Abyss 30th floor World Abyss- WNWY JXTK &5C1 4N3- P4NM 8K&C
The Great Hole but you need a wonder-mail code and the code is: wnwy jxtk &5c1 4n3- p4nm 8k&c.
Cubes of digits 1 - 4n3. (nxnxn) 13 = 1, 23 = 8, 33 = 27...1x1x1 = 12x2x2 = 83x3x3 = 274x4x4 = 645x5x5 = 1256x6x6 = 216
10, 48 and 116. These are derived using the cubic generator: Un = (-4n3 + 27n2 - 47n + 30)/3 for n = 1, 2, 3, ...
This is the wonder mail password to get Giratina: WNWY JXTK &5C1 4N3- P4NM 8K&CThen go to your job list and you will have a job. Then take the job. Then you will be able to go to world abyss. Giratina is in the 30th floor.
There are many possible answers because there are many ways of generating the sequence. One such is the cubic equation, Un = (4n3 - 19n2 + 33n - 16)/2 for n = 1, 2, 3, ... So U5 = 87.
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
The answer depends on which number is missing. Even if the location of the gap is know, there are infinitely many possible solutions. The solutions listed below are polynomials of the lowest degree. First: 5 using the rule Un = (-4n3 + 48n2 - 128n + 99)/3 Second: 0 using the rule Un = (-7n3 + 84n2 - 209n + 138)/6 Third: 21.666 (recurring) using the rule Un = (3n3 - 23n2 + 84n - 61)/3 Fourth: 50 using the rule Un = (-11n3 + 90n2 - 121n + 48)/6 Fifth: 65 using the rule Un = (-4n3 + 36n2 - 44n + 15)/3