-2n
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-4n3 + 8n2 - 4n + 7
10, 48 and 116. These are derived using the cubic generator: Un = (-4n3 + 27n2 - 47n + 30)/3 for n = 1, 2, 3, ...
The answer depends on which number is missing. Even if the location of the gap is know, there are infinitely many possible solutions. The solutions listed below are polynomials of the lowest degree. First: 5 using the rule Un = (-4n3 + 48n2 - 128n + 99)/3 Second: 0 using the rule Un = (-7n3 + 84n2 - 209n + 138)/6 Third: 21.666 (recurring) using the rule Un = (3n3 - 23n2 + 84n - 61)/3 Fourth: 50 using the rule Un = (-11n3 + 90n2 - 121n + 48)/6 Fifth: 65 using the rule Un = (-4n3 + 36n2 - 44n + 15)/3
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
It is 77