Q: Factorise 5x squared plus 17x plus 6?

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12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12

(4x-3)(x+2)

Assuming you mean x squared plus 5x squared... the answer is 6x squared.

-15x2+5x=-5x(3x-1)

-x2+2x

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Factorise: 5x2 + 2x - 192 = (x - 6)(5x + 32) = 0; whence, x = 6 or -6.4.

1

x(x+5)

6x^2 + 5x + 1 = (3x +1) (2x + 1)

12x^3+17x^2+5x=0x(12x^2+17x+5)=0x(x+1)(12x+5)=0x=0x=-1x=-5/12

5x2 + 9x + 13 has no real factors.

(5x - 11)(2x + 1) if the term in x is negative; (5x + 11)(2x - 1) if it's positive.

i got x = 1.35 12x+18=41-5x +5x 17x+18=41 -18 17x=23 /17 x=1.35

5x2-17x+7 (5x-14.60327781)(x-0.4793444384) which is correct to 0.000000001 margin of error

Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7

x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]

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