Q: How do you factorise 3ac-6ad-2bc plus 4bd?

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ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd

(a + 2b)(c + 2d)

ac + 2ad + 2bc + 4bd (ac + 2ad) + (2bc + 4bd) group the figures a(c + 2d) + 2b(c + 2d) remove the common divisors of each set (a + 2b)(c + 2d) take the figures in parentheses as one set, and add the outside figures as the other

(a + 6)(a + 4)

12bc - 4bd - 15xc + 5xd = 4b(3c - d) - 5x(3c - d) = (3c - d)(4b - 5x)

X=5

p2+10d+7

(x+5)(x+3)

5a(2b + 1)

4c(-sq+2)

the answer is x(3+y)

It is: 3(t+3)