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To factorise the expression (3ac - 6ad - 2bc + 4bd), first group the terms: ((3ac - 6ad) + (-2bc + 4bd)). From the first group, factor out (3a), giving (3a(c - 2d)). From the second group, factor out (-2b), yielding (-2b(c - 2d)). Now, combine the factored terms: ((3a - 2b)(c - 2d)).
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Factor this expression check by multiplying factors.4ac plus 2ad plus 2bc plus 4bd?
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
How do you factor this expression ac plus 2ad plus 2bc plus 4bd?
(a + 2b)(c + 2d)
Factoring by grouping ac plus 2ad plus 2bc plus 4bd?
ac + 2ad + 2bc + 4bd (ac + 2ad) + (2bc + 4bd) group the figures a(c + 2d) + 2b(c + 2d) remove the common divisors of each set (a + 2b)(c + 2d) take the figures in parentheses as one set, and add the outside figures as the other
Factorise a a plus 10a plus 24?
(a + 6)(a + 4)
How do you Factor 12bc - 4bd - 15xc plus 5xd?
12bc - 4bd - 15xc + 5xd = 4b(3c - d) - 5x(3c - d) = (3c - d)(4b - 5x)
How do you factorise 3x plus 15?
X=5
How do you Factorise p2 plus 10d plus 7?
p2+10d+7
Factorise x2 plus 8x plus 15?
(x+5)(x+3)
How do you factorise -4csq plus 8c?
4c(-sq+2)
How do you factorise 3t plus 9?
It is: 3(t+3)
How do you factorise 4x plus 24?
4(x+6)
How do you factorise 3x plus 6?
It is: 3(x+2)
