Take the derivative of the function.
By plugging a value into the derivative, you can find the instantaneous velocity.
By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.
Example:
Find the instantaneous velocity at x = 3 and find the maximum height.
f(x) = -x2 + 4
f'(x) = -2x
f'(3) = -2*3 = -6
So the instantaneous velocity is -6.
0 = -2x
0 = x
So the maximum height occurs at x = 0
f(0) = -02 + 4 = 4
So the maximum height is 4.
It is the gradient (slope) of the line.
1/2mv^2 = mgh
the final velocity assuming that the mass is falling and that air resistance can be ignored but it is acceleration not mass that is important (can be gravity) final velocity is = ( (starting velocity)2 x 2 x acceleration x height )0.5
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
There is insufficient information to answer the question.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.
There is average velocity, and there is instantaneous velocity. I don't think "overall velocity" is a concept generally used in physics; please clarify what you mean.
It is the gradient (slope) of the line.
If the displacement of the object (its position) can be described as a functional or algebric equation, you can find the instant speed of this object by calculating the derivative of its displacement equation, knowing that speed is the first derivative of position and acceleration, its second.
body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range
Multiply the height by 4. The equation to use is h=-16t2 + v0t + h0. Use whatever values you want for v0 and h0, and find the vertex of the parabola. Then double your value of v0, and find the vertex of your new parabola. It will be 4 times as high every time. By the way, to find the vertex, plug in v0/32 for t. Then solve for h.
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
average acceleration is the average of the acceleration of a body in its entire motion where as instantaneous acceleration is the rate of change of velocity at an instant. it may be a function of time or velocity or displacement.
In that case, you don't have enough information.
1/2mv^2 = mgh