0
What else can I help you with?
Find the area of parallelogram?
To find the area of a parallelogram, multiply the length of the base by the height. The height should be perpendicular to the base.
How do you find the area if a parallelogram?
Area = length*perpendicular height
What do you need to know to find the area of a parallelogram?
Its length and its perpendicular height Area = length*height
What is the length for a parallelogram?
A parallelogram can have any length which is greater than zero.
How can you find the area of a parallelogram if you only know the side lengths?
The area of a parallelogram is equal to base times height. You can find the maximum area of a parallelogram by multiplying the length of a short side by the length of a long side. (This would be the area if the parallelogram were a rectangle.)You cannot know the area of a parallelogram if all you know is the length of the sides; you can only know the maximumpossible area. Imagine you slant the parallelogram a lot. The area will decrease, but the side lengths will stay the same.
If a parallelogram has an area of 115 square units and a base length of 12 what is the height of the parallelogram to the nearest hundredth?
To find the height of a parallelogram, you divide the area by the base length. So in this case, the height of the parallelogram would be 115/12 = 9.58 to the nearest hundredth.
How do you find the area of a parallelogram with only the perimeter?
area is length times width
What is the equation to find the area in a parallelogram?
Multiply the length of the base by the vertical height.
What do you do when you need to find the area of a parllagram?
Area of a parallelogram = length*perpendicular height
How do you find the ratio of two corresponding sides in a parallelogram?
Divide the length of one side by the length of an adjacent side.
What is the length property of a parallelogram?
The base length of a parallelogram is larger than its width or its side.
How do you find the height of a parallegram with just length and wide?
You cannot. Also, it is a parallelogram, not parallegram!
