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∙ 9y agoLet the length be x:
2*x = perimeter-(2*breadth)
Then divide both sides by 2 to find the vallue of x
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∙ 9y agowe have the formula to find perimeter of the rectangle i.e. perimeter = 2(l+b) where l = length b = breadth substitute l=96 and perimeter = 334,we get 334 = 2(96+b) 334/2=96+b, 167 = 96 + b b = 167-96 =71. b = breadth of the given rectangle is 71.
let the length be 'x' and the breadth be 'y' then area = xy and perimeter = 2x+2y Solve the simultaneous linear equations by given area and perimeter. Regards, A Pakistani!
If the given dimensions are the length and width of a rectangle then its perimeter is 15.6+4.5+15.6+4.5 = 40.2
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
by appying 2l+2w
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
2(length+breadth)=Perimetre Length= (Perimetre/2)-Breadth Area=Length x breadth
Divide the area by the length of the rectangle
All you need to do is length x breadth = area
we have the formula to find perimeter of the rectangle i.e. perimeter = 2(l+b) where l = length b = breadth substitute l=96 and perimeter = 334,we get 334 = 2(96+b) 334/2=96+b, 167 = 96 + b b = 167-96 =71. b = breadth of the given rectangle is 71.
l = Length W = breadth or width perimeter = 2 x (L+W) = 2L + 2W
A rectangle is a 2-dimensional object. It cannot have length and breadth AND height. If three dimensions are given, then two of them (eg breadth and height) must stand for the same thing.
let the length be 'x' and the breadth be 'y' then area = xy and perimeter = 2x+2y Solve the simultaneous linear equations by given area and perimeter. Regards, A Pakistani!
Perimeter = 2*(L + W).
Length = (Perimeter - twice width) / 2
The breadth of a rectangle is the height.
If the given dimensions are the length and width of a rectangle then its perimeter is 15.6+4.5+15.6+4.5 = 40.2