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Q: What is the area of the rectangle when the length and breadth are given?

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length*breadth

include<stdio.h> #include<conio.h> void main() { int length, breadth, area ; printf("\n Enter the length & breadth of a Rectangle"); scanf("d",&length,&breadth); area=length*breadth; printf("\n Area of the Rectangle=%d",area); getch(); }

The formula for the area of a rectangle is length x breadth. In order to prove this works, work out an area of a rectangle using that formula.

the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width

You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.

Related questions

Divide the area by the length of the rectangle

2(length+breadth)=Perimetre Length= (Perimetre/2)-Breadth Area=Length x breadth

If you do not know the length or breadth of a rectangle, you cannot know the area. If you do not know the area of a rectangle, you cannot know the length and breadth. To know the length and breadth of a rectangle, you have to know some other contributing factor in the equation. If you don't, measure it!

length*breadth

Area of rectangle = length * breadth

Area of rectangle = length * breadth or length * width

multiply the length with the breadth.

product of length and breadth

breadth multipied by the length

int length int breadth int area= (length x breadth) print area

#include<stdio.h> void main() { float length, breadth, area, perimeter; printf("Enter the length & breadth of a Rectangle\n(length breadth): "); scanf("%f %f",&length,&breadth); area=length*breadth; perimeter=2*(length+breadth); printf(" Area of the Rectangle=%0.3f\n",area); printf("Perimeter of the Rectangle=%0.3f\n",perimeter); printf("(Press ENTER to exit.)"); getch(); printf("\n"); }

length * breadth. (or, can be said as - length times width)

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