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L x B which gives the area of th rectangle then remaining we will have 4 equator triangle 1/3BH3 is the are for the triangle. cumulatively we will get area for the hexagan.

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Q: How do you find the area of a hexagon given the area of the rectangle formed by 2 diagonals and 2 sides of the hexagon?
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In a given quadrilateral each side is parallel to its opposite side and the diagonals are not perpendicular What could it be?

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The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.


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How do you find the number of sides of a polygon given the number of diagonals?

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What is the area of hexagon?

(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.