Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals.
Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
number of diagonals = n(n-3)/2 n - number of sides of the polygon
1/2*(n2-3n) = 665 diagonals where n means number of sides
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
A polygon with n sides has n*(n - 3)/2 diagonals. So n = 23 gives 23*20/10 = 230 diagonals
There is no such polygon that fits the given information.
A 7 sided polygon has 14 diagonals
The five sided Polygon has 5 diagonals
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
38 diagonals
It has 20 diagonals
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A polygon with 14 diagonals will have 7 sides
11
209
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon