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How do you find the equation of a line that is perpendicular to y equals 9 divided by 8x plus 1 and passes through the point 18 -8?
Wiki User
∙ 12y ago
The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.
Wiki User
∙ 12y ago
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