The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.
y=-x
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5
0.5
15
y=-x
It would be perpendicular to a line with the equation Y = 1/8 X.
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
"Y = any number" is perpendicular to "x = -3".
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
No because the slope of the second equation is 1/4 and for it to be perpendicular to the first equation it should be 1/3
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
It could be y = -x+5
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
6