y = 2x + 2 + 4x+ 2 = 6x + 4
This is NOT a symmetric function and so there is no axis of symmetry.
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
X= -b / 2a
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
Call the intercept with the y-axis b. The equation for the line is then y=5x+b With the information about the x-intercept we get: 0=5*7+b b=-35
For example, y = ax2 + bx + c (the equation of a parabola). Every parabola has an axis of symmetry and the graph to either side of the axis of symmetry is a mirror image of the other side. It means that if we know a point on one side of the parabola, we can find its symmetric point to the other side, based on the axis of symmetry. Those symmetric points have opposite x-coordinate values, and the same y-coordinate value. The vertex only is a single point which lies on the axis of symmetry.
Your equation must be in y=ax^2+bx+c form Then the equation is x= -b/2a That is how you find the axis of symmetry
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
Complete the square, then find the value of x that would make the bracket zero ax^2 + bx + c = 0 line of symmetry is x = (-b/2a)
X= -b / 2a
Once you calculate the X coordinate using the axis of symmetry (X=-b/2a), you plug that value in for all of the X's in the equation of the parabola. You then solve the equation for the value of Y.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
Call the intercept with the y-axis b. The equation for the line is then y=5x+b With the information about the x-intercept we get: 0=5*7+b b=-35
x = -4 The equation to find this is -b/2a with 8 being the b and 1 being the a.
For example, y = ax2 + bx + c (the equation of a parabola). Every parabola has an axis of symmetry and the graph to either side of the axis of symmetry is a mirror image of the other side. It means that if we know a point on one side of the parabola, we can find its symmetric point to the other side, based on the axis of symmetry. Those symmetric points have opposite x-coordinate values, and the same y-coordinate value. The vertex only is a single point which lies on the axis of symmetry.