3 and p2 are both factors of each part of the binomial, so divide it from each part and see what you have left. (3p4 / 3p2) - (12p2 / 3p2) (3p2)(p2-4)◄
The quadratic cannot be factorised. Its roots are irrational.
p2+10d+7
This quadratic expression can not be factored because its discriminant is less than zero.
(p - 9)(p - 9)
p2+2pq+q2=1
p2 - 25 = (p - 5)(p + 5)
P2 + l 2 + w
p2 + 3p = p (p + 3)
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
rutherford