Multiples of 12 are even. Start with 999998. It's not divisible by 12. Try 999996. It is divisible by 12. Stop there.
The greatest four-digit number is 9999. To find the largest four-digit number divisible by nine, we can check if 9999 is divisible by nine by summing its digits: 9 + 9 + 9 + 9 = 36, which is divisible by nine. Therefore, the greatest four-digit number that is divisible by nine is 9999 itself.
The greatest four-digit number is 9999. To find the largest four-digit number exactly divisible by 24, we can divide 9999 by 24, which gives approximately 416.625. Multiplying 416 by 24 gives 9996, making 9996 the greatest four-digit number that is exactly divisible by 24.
The greatest number that is a multiple of both 2 and 5 is their least common multiple (LCM), which is 10. Since you are looking for the greatest number of 3, you can find the largest multiple of 10 that is less than or equal to 3, which is 0. Therefore, the greatest number of 3 that is divisible by both 2 and 5 is 0.
To find the greatest four-digit number divisible by more than one number, start with the largest four-digit number, which is 9999. Check its divisibility by the desired numbers (e.g., 2, 3, 5, etc.). If 9999 is not divisible by those numbers, decrement by 1 and check again until you find a number that meets the criteria. This process continues until you identify the largest four-digit number that is divisible by at least two specified numbers.
The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9
The greatest number that both 42 and 56 are divisible by is their greatest common divisor (GCD). To find the GCD, we can use the prime factorization method: 42 can be factored into (2 \times 3 \times 7) and 56 into (2^3 \times 7). The common factors are (2) and (7), and the GCD is (2 \times 7 = 14). Therefore, the greatest number that both 42 and 56 are divisible by is 14.
If the last two digits of a number are divisible by 4, the whole number is divisible by 4.
1) Find the least common multiple of 3, 4, and 5. 2) Divide the greatest possible 6-digit number (999,999) by this number. 3) Discard the decimal part, and multiply the result again by this greatest common factor.
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
To find the greatest 3-digit number divisible by both 5 and 9, we need to find the highest common multiple of 5 and 9 within the range of 100 to 999. The highest common multiple of 5 and 9 is 45. To find the greatest 3-digit number divisible by 45, we divide 999 by 45, which equals 22 with a remainder. Therefore, the greatest 3-digit number divisible by both 5 and 9 is 45 x 22 = 990.
Divide it by 11. If the answer is a whole number, it's divisible.
If the last number is divisible by 4 then the whole number is divisable by 4