Multiples of 12 are even. Start with 999998. It's not divisible by 12. Try 999996. It is divisible by 12. Stop there.
The lowest common multiple of 5 and 9 is 45 and 11 times 45 is 495 which is the greatest 3 digit number divisible by 5 and 9
If the last two digits of a number are divisible by 4, the whole number is divisible by 4.
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
Divide it by 11. If the answer is a whole number, it's divisible.
1) Find the least common multiple of 3, 4, and 5. 2) Divide the greatest possible 6-digit number (999,999) by this number. 3) Discard the decimal part, and multiply the result again by this greatest common factor.
To find the greatest 3-digit number divisible by both 5 and 9, we need to find the highest common multiple of 5 and 9 within the range of 100 to 999. The highest common multiple of 5 and 9 is 45. To find the greatest 3-digit number divisible by 45, we divide 999 by 45, which equals 22 with a remainder. Therefore, the greatest 3-digit number divisible by both 5 and 9 is 45 x 22 = 990.
If the last number is divisible by 4 then the whole number is divisable by 4
Do the division and if the remainder is 0 then the number is divisible by the something and if not it isn't.
To find out if a number is divisible by 8 the number must be divisible by 2 and 4!
To find the greatest four-digit number that is divisible by 15, 20, and 25, we need to find the least common multiple (LCM) of these three numbers. First, let's find the prime factorization of each number: 15 = 3 × 5 20 = 2 × 2 × 5 25 = 5 × 5 The LCM will be the product of the highest powers of each prime factor that appears in any of the numbers: LCM = 2^2 × 3^1 × 5^3 = 4 × 3 × 125 = 1,500 So, the greatest four-digit number that is divisible by 15, 20, and 25 is 1,500. Answer: 1,500
It is easier to find the lowest common number, then getting the largest multiple of that that is under 10000. The LCM is 4680, x2 is 9360.
The smallest number that is divisible by 18 and 48 is 144.