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∫ tan(x) dx =
∫ sin(x)/cos(x) dx
Let cos(x) = u
Therefore, sin(x) = -du/dx >>>> (Derivative of cos(x))
∫ (-du/dx)/u dx >>>>>>>>>>> Substitute the values
∫ -du/udx dx
∫ -du/u >>>>>>>>>>>>>>>>> dx * 1/dx cancel each other out
∫ -1/u du
= -ln(u) + C
= -ln(cos(x)) + C >>>>>>>>>>> Substitute cos(x) back into u
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∙ 12y ago
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What is the integral of tanx times sqrt secx dx?
See related link below for answer
What is the integral of underroot tanx plus underroot cotxdx?
It isn't clear what you mean by "underroot"; I am not aware of a mathematical function by that name.
When was Tanx created?
Tanx was created in 1972-10.
Tan plus cot divided by tan equals csc squared?
(tanx+cotx)/tanx=(tanx/tanx) + (cotx/tanx) = 1 + (cosx/sinx)/(sinx/cosx)=1 + cos2x/sin2x = 1+cot2x= csc2x This is a pythagorean identity.
What is the Derivative of -x plus tanx?
(-x+tanx)'=-1+(1/cos2x)
Integration of tan pow4x?
integral of (tanx)^4 (tanx)^4 = (tanx)^2 (tanx)^2 =(sec^2 x - 1)(tan^2 x) =(sec^2 x)(tan^2 x) - tan^2 x = integral of sec^2 x tan^2 x dx - integral of tan^2 x dx First, integral of sec^2 x tan^2 x dx Let u = tanx because that would make du = sec^2 x dx so then we have integral of u^2 du which is (1/3)u^3 substituting back in tanx we get (1/3)tan^3 x Next, integral of tan^2 x tan^2 x = sec^2 x -1 integral of sec^2 x - 1 = integral of sec^2 x dx - integral 1 dx = tanx - x so putting it all together we have integral of tan^4 x dx = (1/3)tan^3 x - tanx + x + C
What is the integral of tanx times sqrt secx dx?
See related link below for answer
What is the integral of tan cubed x secx dx?
This is a trigonometric integration using trig identities. S tanX^3 secX dX S tanX^2 secX tanX dX S (secX^2 -1) secX tanX dX u = secX du = secX tanX S ( u^2 - 1) du 1/3secX^3 - secX + C
What is the integral of underroot tanx plus underroot cotxdx?
It isn't clear what you mean by "underroot"; I am not aware of a mathematical function by that name.
Integration of root tanx?
The integral of sqrt(tan(x)) is rather complex and is hard to show with the formatting allowed on Answers.com. See the related links for a representation of the answer.
When was Tanx created?
Tanx was created in 1972-10.
Integration of square root tan x dx?
for solving this ..the first thing to do is substitute tanx=t^2 then x=tan inverse t^2 then solve the integral..
Tan plus cot divided by tan equals csc squared?
(tanx+cotx)/tanx=(tanx/tanx) + (cotx/tanx) = 1 + (cosx/sinx)/(sinx/cosx)=1 + cos2x/sin2x = 1+cot2x= csc2x This is a pythagorean identity.
What is the Derivative of -x plus tanx?
(-x+tanx)'=-1+(1/cos2x)
Intergrate sec x?
Sec x dx = sec x (secx + tanx)/ (secx + tanx) dx . therefore the answer is ln |secx + tanx|
How do you simplify tanx plus 1 sqaured?
I assume you mean (tanx+1)^2 In which case, (tanx+1)^2=tan2x+2tanx+1
What is the derivative of 1 plus tanx?
d/dx(1+tanx)=0+sec2x=sec2x
