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The sum of the first n natural numbers is n*(n+1)/2

There are n numbers so their mean = (n+1)/2

Q: How do you find the mean of first n natural numbers?

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Mean = (sum of the n numbers)/n

The natural numbers are positive integers (whole numbers) starting from one. So, the first natural number is 1, the second natural number is 2, the third is 3, and so on.

To find the mean you first have to add up all the numbers then you divide it by how many numbers you have and you got the mean. Example: 12+13+5=30 30/3=10 10 is the mean

Their mean is 3.

That depends what the numbers are.

Related questions

Mean = (sum of the n numbers)/n

1 Sum of first n natural numbers = n(n+1)2[Formula.]2 Arthmetic mean of first n natural numbers = Sum of the numbers n[Formula.]3 = n(n+1)2n = n+124 So, the Arthmetic mean of first n natural numbers = n+12

1,2,3,4,5,6,7,8,9,10,11,12,13,14, etc.

The first natural number is usually taken to be 1. The mean of one number is itself so the mean of the first natural number is 1.

The natural numbers are positive integers (whole numbers) starting from one. So, the first natural number is 1, the second natural number is 2, the third is 3, and so on.

The mean of numbers is the average. To find this, first add all the numbers, then divide by how many numbers you added.

38.5

To find the mean you first have to add up all the numbers then you divide it by how many numbers you have and you got the mean. Example: 12+13+5=30 30/3=10 10 is the mean

If you mean larger by "the set of whole numbers strictly contains the set of natural numbers", then yes, but if you mean "the set of whole numbers has a larger cardinality (size) than the set of natural numbers", then no, they have the same size.

Their mean is 3.

That depends what the numbers are.

"Natural Numbers" can mean either "Counting Numbers" {1, 2, 3, ...}, or "Whole Numbers" {0, 1, 2, 3, ...}, depending on the subject.