Un = n*(n2 + 3n + 2)/6 or n*(n+1)*(n+2)/6 for n = 1, 2, 3, ...
560
They are: nth term = 6n-4 and the 14th term is 80
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
20-9x=n
560
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
It is: nth term = 6n-4
t(n) = n2 + n + 8
The nth term is: 5n
The nth term of the sequence is expressed by the formula 8n - 4.
The nth term of this sequence is 3n + 4
They are: nth term = 6n-4 and the 14th term is 80
f(n) = 14 - 6n -6n+20
The first term is 10. Dividing (say) the 3rd term by the 2nd term gives 40/20 = 2 Dividing any two successive terms in this manner results in the same answer. Then 2 is the common ratio. The general formula for the nth term of a Geometric Progression or Series is :- a(n) = ar^n-1.....where a is the first term and r is the common ratio. For the pattern provided, a(n) = 10 x 2^n-1
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
Divide the sequence by 5 and the answer becomes very obvious: 1, 4, 9, 16,...N2 So, 5, 20, 45, 80,...5N2