560
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
The nth term is: 5-2n
It is: nth term = 5-4n and so the next term will be -19
To find the nth term of the sequence 5, 15, 29, 47, 69, we first determine the differences between consecutive terms: 10, 14, 18, and 22. The second differences are constant at 4, indicating that the nth term is a quadratic function. By fitting the quadratic formula ( an^2 + bn + c ) to the sequence, we find that the nth term is ( 2n^2 + 3n ). Thus, the nth term of the sequence is ( 2n^2 + 3n ).
The sequence 5, 10, 20, 40, 80 can be identified as a geometric progression where each term is multiplied by 2. The nth term can be expressed as ( a_n = 5 \times 2^{(n-1)} ), where ( a_n ) is the nth term. Thus, for any integer ( n ), you can find the term by substituting ( n ) into this formula. For example, the 1st term is 5, the 2nd term is 10, and so on.
The nth term is: 5n
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
25
1. -52. 103. -154. 205. -256. 307. -358. 409. -45
The nth term is: 3n+2 and so the next number will be 20
To find the nth term of this sequence, we first need to identify the pattern. The differences between consecutive terms are 5, 9, 13, 17, and so on. These are increasing by 4 each time. This means that the nth term can be calculated using the formula n^2 + 4n + 1. So, the nth term for the sequence 5, 10, 19, 32, 49 is n^2 + 4n + 1.
The nth term is: 5-2n
n+4
5n-5, because its the 5 time table (called 5n) minus 5 each time
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
6n-5 is the nth term of this sequence