The sequence 5, 10, 20, 40, 80 can be identified as a geometric progression where each term is multiplied by 2. The nth term can be expressed as ( a_n = 5 \times 2^{(n-1)} ), where ( a_n ) is the nth term. Thus, for any integer ( n ), you can find the term by substituting ( n ) into this formula. For example, the 1st term is 5, the 2nd term is 10, and so on.
It's 10 i think...a lol
The LCM of 8, 10, and 20 is 40. Multiples of 8: 8, 16, 24, 32, 40, 48...... Multiples of 10: 10, 20, 30, 40, 50, 60...... Multiples of 20: 20, 40, 60, 80 The smallest number that all three numbers go into evenly is 40. Therefore the LCM of 8, 10, and 20 is 40.
-20 and -20 10 and -50 40 and -80
Two of the factors of 40 are odd. The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40
The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40.
6n+10
Say if you had the pattern 15 20 25 30 35 40 45 50 To find the nth term you have to see what the gap between the numbers is. In our case this is 5. Then you have to find out what the difference between the gap and the first number. In this sequence it is 10. So your answer would be..... 5n+10 That's how you find the nth term.
The nth term is 2n So the 20th term is 2 x 20 = 40.
Oh, dude, finding the nth term for this pattern is like finding your favorite socks in the laundry - tedious but doable. So, to get from 10 to 20, you multiply by 2, then by 2 again to get 40, then 80, then 160. So, the pattern is just doubling each time. That means the nth term is 10 times 2 to the power of n-1. Easy peasy!
To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
To find the nth term of a sequence, we first need to identify the pattern. In this case, it appears that the sequence is increasing by consecutive odd numbers: 3, 5, 7, 9, 11, etc. Therefore, the nth term can be calculated using the formula: nth term = a + (n-1)d, where a is the first term (5), n is the term number, and d is the common difference (3 for this sequence). So, the nth term for this sequence would be 5 + (n-1)3, which simplifies to 3n + 2.
Any number that you choose can be the nth number. There are infinitely many rules, based on a polynomial of order 5, such that the first five numbers are as listed in the question. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.Using the principle of Occam's razor, the answer isU(n) = 10*n
4 10 16 22 28 34 40 ....... Each term is increased by 6 or nth term = 6n-2
The given sequence is an arithmetic sequence with a common difference of 5. To find the nth term of an arithmetic sequence, we use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 0) and the common difference (d = 5). Therefore, the nth term of the sequence is (a_n = 0 + (n-1)5 = 5n - 5).
These may help you answer your questions: 1, 2, 4, 5, 8, 10, 20 and 40.
|-20 - (-40)| = 20 |-20 - 10| = 30 -20 is closer to -40 than 10.
40 is the outlier of10 15 10 20 10 20 40