width + length x 2
or
w + l x 2
or
w + L2
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
the width equals 14 cm. and the length equals 31 cm.
Area is length times width, perimeter is twice the sum of length and breadth.
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
Length = (Perimeter - twice width) / 2
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
20 cm