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Q: How do you find the terminal and initial points of a vector?
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Find a vecot equivalent to the vector PQ with its initial point at the origin and find the magnitude of the vector P equals -4 -3 Q equals -2 2?

vector PQ where P(-4, -3) and Q(-2, 2) equivalent vector P'Q' where P'(0, 0) and Q'(2, 5) the magnitude doesn't change so we can compute |P'Q'| = √(22 + 52) = √29


How do you find a point that is collinear with four points?

The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.


How do you find missing vector if resultant is given?

The Resultant Vector minus the other vector


When vector is divided by its own magnitude you find its?

We get the Unit Vector


How can you find a unit vector in the same direction as the given vector?

Divide the vector by it's length (magnitude).


How do you find vector components when given the vectors are parallel and the magnitude of each vector is equal to 1?

If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.


How can you find the direction of a moving object?

Determine the position of the object at two different times. The vector joining the first with the second of those positions points in the direction of the objects motion.


How do you find the component of a vector perpendicular to another vector?

The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.


Find a unit vector in the direction from 3 -1 4 to 1 3 5?

find the vector<1,1>+<4,-3>


How do you find the normal vector of a ball or sphere?

The normal vector to the surface is a radius at the point of interest.


Vector method to find out the acceleration of a particle is -wwrwhere angular velocity is w?

1) The position vector of a particle is r= (a cosώt) i+ (a sinώt) j. The velocity of the particle is and find the parallel position vector.


How to find the direction of vector A by its x and y components?

Consider any two points on the vector, P = (a, b) and Q = (c, d). And lext x be the angle made by the vector with the positive direction of the x-axis. Then either a = c, so that the vector is vertical and its direction is straight up or a - c is non-zero. In that case, tan(x) = (b - d)/(a - c) or x = tan-1[(b - d)/(a - c)]