If those numbers are length x width, the "width" usually refers to the smaller of the two numbers.
It is: 2(32+56) = 176 feet
If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4
7 feet
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
LxW=4032 5W=L+34 5W^2-34W=4032 W=32 Length=126
8 length 8 width
It is: 2(32+56) = 176 feet
32 cm
If the area of a rectangle is found by measuring the length times the width, then if you know the area is 256 and the width is 8, you find the length by dividing 256 by 8 which would give you a length of 32 centimeters.
If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4
32
32 cm
32
7 feet
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
I assume redtangle is supposed to be rectangle? So the formula to find the area is length x width. For example: rectangle is 8" x 4" so 8 x 4 = 32 square inches (32in2).