answersLogoWhite

0

8 length 8 width

User Avatar

Wiki User

15y ago

What else can I help you with?

Related Questions

What is the length and width of a table top that is haped like a rectangle whose perimeter is 73.4inches and the length is 4.7 inches?

Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.


What is the width of a rectangle with the perimeter of 32 feet and length of 9 feet?

7 feet


What is the perimeter of a rectangle whose with is 6?

I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.


What is the perimeter of a rectangle with a length of 7 units and a width of 9 units?

Perimeter = 2*(7+9) = 32 units.


What is the perimeter and area of a rectangle with 5 in length and 11 in width?

Perimeter = 32 inches. Area = 55 square inches.


What has the greater perimeter a square with side eight units or rectangle with length 14 units and width two units?

They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units


What is the perimeter of rectangle with a length of 45 cm and a width of 32 cm?

Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.


What is the perimeter and area of rectangle 14cm by 32 cm?

To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.


Find the perimeter of a rectangle with a length of 32 feet and a width of 56 feet?

It is: 2(32+56) = 176 feet


What is the area of a rectangle with a perimeter of 24 and a length of 8?

32


The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?

Let the width be x feet. Then, the length would be (x+7) feet. Given that decreasing the length by 3 feet and increasing the width by 2 feet gives a perimeter of 32 feet, you can set up the equation 2( (x+7) - 3 + x + 2) = 32 to find the original width x and length (x+7).


If Perimeter of a rectangle that has a width of x inches and a length of x plus 16 inches is 2x plus 2x plus 16 inches simplify the expression for the perimeter Find the perimeter if x equals 14?

If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.