8 length 8 width
Perimeter = 2*(7+9) = 32 units.
Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.
32 cm
w= widthw+4=length2(w+l)= perimeter2(w+w+4)=32 substitution2(2w+4)=324w+8=32 distributive property4w=32-8 subtraction property of equality4w=24w=6 division property of equalitylength is 6+4 or 10cm.
6
Length + width = half of perimeter ie 36.7 in. If length is 4.7 in then width is 32 in.
7 feet
I think you mean the width is 6. The answer depends entirely on what the length of the rectangle is. For example, if it is a square, so that the length and width are both 6, the answer is 24. I the length is 10, the perimeter is 32. In general, just add the width (6) to the length and double the sum to get the perimeter.
Perimeter = 2*(7+9) = 32 units.
Perimeter = 32 inches. Area = 55 square inches.
They will be both the same because the perimeter of the square is 32 units and the perimeter of the rectangle is also 32 units
Perimeter = 2*(L + W)= 2*(45 + 32) = 2*77 = 154 cm.
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
It is: 2(32+56) = 176 feet
32
Let the width be x feet. Then, the length would be (x+7) feet. Given that decreasing the length by 3 feet and increasing the width by 2 feet gives a perimeter of 32 feet, you can set up the equation 2( (x+7) - 3 + x + 2) = 32 to find the original width x and length (x+7).
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.