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How do you find three consecutive integers that have a sum of -12?
Wiki User
∙ 12y ago
X + (X + 1) + (X + 2) = - 12
3X + 3 = - 12
3X = - 15
X = - 5
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- 5 + ( - 5 + 1) + (- 5 + 2) = - 12
- 5 + ( - 4) + ( - 3) = -12
- 12 = -12
----------------so,
( - 3, - 4, - 5 ) are the three consecutive integers
Wiki User
∙ 12y ago
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