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How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?
tan theta = sqrt(2)/2 = 1/sqrt(2).
Is sqrt 2 plus sqrt 2 equals 4?
No
How can you find the area of a hexagon if you already have the perimeter?
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
What is the square root of eight divided by 2 square root of three?
sqrt(8)/[2*sqrt(3)] = 2*sqrt(2)/[2*sqrt(3)] = sqrt(2)/sqrt(3) = sqrt(2/3)
How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
How do you simplify the square root of 12 divided by 2?
6
If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?
tan theta = sqrt(2)/2 = 1/sqrt(2).
Is sqrt 2 plus sqrt 2 equals 4?
No
How can you find the area of a hexagon if you already have the perimeter?
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
What is the square root of eight divided by 2 square root of three?
sqrt(8)/[2*sqrt(3)] = 2*sqrt(2)/[2*sqrt(3)] = sqrt(2)/sqrt(3) = sqrt(2/3)
How do you do sqrt 8 divided by 28?
0.2857
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
If hx equals f o g x and hx equals sqrt x plus 5 find gx if fx equals sqrt x plus 2?
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
What is x if the sin of x equals square root of 5 divided by 2?
2.5
What is the square root of 98 divided by the square root of 2?
49
Square root of 98 divided by square root of 2?
49
