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What is the answer of 2 plus root 2 the whole square?
For (a + b)² = a² + 2ab + b². So (2 + sqrt(2))² = 2² + 2*2*sqrt(2) + (sqrt(2))² = 4 + 4*sqrt(2) + 2, which equals 6 + 4*sqrt(2) = approx 11.6569Alternately:-The value of sqrt(2) is appx 1.414So ( 2 + sqrt(2) )2 = ( 2 + 1.414 )2= (3.414)2= 11.65
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
Solve the quadratic equation x2 plus 6x plus 41 equals 0?
x = [-6 +/- sqrt(62-4*1*41)]/2 =[-6 +/- sqrt(36-164)]/2 =[-6 +/- sqrt(-128)]/2 = -3 +/- sqrt(-32) = -3 +/- i*sqrt(32) where i = the imaginary sqrt of -1
Square root of 3x plus 4 equals 2?
sqrt( 3x + 4 ) = 23x + 4 = 43x = 0x = 0Marvelous.
Ax2 plus bx plus c equals 0?
x=(-b+sqrt(b^2-4*a*c))/(2a) and (-b-sqrt(b^2-4*a*c))/(2a) (This is called the quadratic formula)
