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What is the answer of 2 plus root 2 the whole square?
For (a + b)² = a² + 2ab + b². So (2 + sqrt(2))² = 2² + 2*2*sqrt(2) + (sqrt(2))² = 4 + 4*sqrt(2) + 2, which equals 6 + 4*sqrt(2) = approx 11.6569Alternately:-The value of sqrt(2) is appx 1.414So ( 2 + sqrt(2) )2 = ( 2 + 1.414 )2= (3.414)2= 11.65
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
Ax2 plus bx plus c equals 0?
x=(-b+sqrt(b^2-4*a*c))/(2a) and (-b-sqrt(b^2-4*a*c))/(2a) (This is called the quadratic formula)
Solve the quadratic equation x2 plus 6x plus 41 equals 0?
x = [-6 +/- sqrt(62-4*1*41)]/2 =[-6 +/- sqrt(36-164)]/2 =[-6 +/- sqrt(-128)]/2 = -3 +/- sqrt(-32) = -3 +/- i*sqrt(32) where i = the imaginary sqrt of -1
Square root of 3x plus 4 equals 2?
sqrt( 3x + 4 ) = 23x + 4 = 43x = 0x = 0Marvelous.
X2 plus 2x-4 equals 0?
x2+2x-4 = 0 x = (-2 plus/minus sqrt (4-(4x1x-4)) / 2 x = (-2 plus/minus sqrt 20)/2 x = (-2 - sqrt 20)/2 or (-2 + sqrt 20)/2 x = -3.236 or 1.236
Y equals 4x2 plus 6x - 1?
Y = 4x2 + 6x - 1Use the pq-formula:x = -4/2 +- sqrt ((4/2)2 -(-1))x = -2 +- sqrt((16/4) +1)x = -2 +- sqrt(4 +1)x1 = -2 + sqrt(5)x2 = -2 - sqrt(5)
What is the answer of 2 plus root 2 the whole square?
For (a + b)² = a² + 2ab + b². So (2 + sqrt(2))² = 2² + 2*2*sqrt(2) + (sqrt(2))² = 4 + 4*sqrt(2) + 2, which equals 6 + 4*sqrt(2) = approx 11.6569Alternately:-The value of sqrt(2) is appx 1.414So ( 2 + sqrt(2) )2 = ( 2 + 1.414 )2= (3.414)2= 11.65
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
Ax2 plus bx plus c equals 0?
x=(-b+sqrt(b^2-4*a*c))/(2a) and (-b-sqrt(b^2-4*a*c))/(2a) (This is called the quadratic formula)
Solve the quadratic equation x2 plus 6x plus 41 equals 0?
x = [-6 +/- sqrt(62-4*1*41)]/2 =[-6 +/- sqrt(36-164)]/2 =[-6 +/- sqrt(-128)]/2 = -3 +/- sqrt(-32) = -3 +/- i*sqrt(32) where i = the imaginary sqrt of -1
Square root of 3x plus 4 equals 2?
sqrt( 3x + 4 ) = 23x + 4 = 43x = 0x = 0Marvelous.
2wsquared plus 22w plus 7 equals 0?
2w2 + 22w + 7 = 0 w = [-22 +/- sqrt(22*22 - 4*2*7)] / (2*2) = [-22 +/- sqrt(484 - 56)] / 4 = [-22 +/- sqrt(428)] / 4 so w = -0.328 or w = -10.672
What is X2-4x plus 1 equals 0 by completing the square?
x2 - 4x + 1 = 0p=4q=1x = -p/2 +- sqrt((p/2)2 - q)x = -4/2 +- sqrt((4/2)2 - 1)x = -2 +- sqrt(4-1)x1= -2 + sqrt(3)x2= -2 - sqrt(3)
How do you solve x squared plus 4x-3 equals 0 in surd form?
x2 + 4x - 3 = 0 The quadratic formula is x = {-4 ± sqrt[(-4)2 - 4*1*(-3)]}/2 = {-4 ± sqrt[16 + 12]}/2 = {-4 ± sqrt[28]}/2 = {-4 ± 2*sqrt[7]}/2 = -2 ± sqrt[7]
What is the square root of 8 plus the square root of 8?
sqrt(8) + sqrt(8) = 2 sqrt(8) = 2 sqrt(4 x 2) = 2 sqrt(4) sqrt(2) = 2 x 2 sqrt(2) = 4 sqrt(2) = 5.657(rounded)
What is the square root x plus 5 equals 9?
sqrt(x) + 5 = 9 so sqrt(x) = 9 - 5 = 4 so x = 4^2 = 16
