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To solve the equation ( \frac{2 \sqrt{x}}{c} = y ) for ( x ), first multiply both sides by ( c ) to isolate the square root term: ( 2 \sqrt{x} = yc ). Then, divide both sides by 2: ( \sqrt{x} = \frac{yc}{2} ). Finally, square both sides to solve for ( x ): ( x = \left(\frac{yc}{2}\right)^2 ).
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How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?
tan theta = sqrt(2)/2 = 1/sqrt(2).
Is sqrt 2 plus sqrt 2 equals 4?
No
How can you find the area of a hexagon if you already have the perimeter?
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
What is the square root of eight divided by 2 square root of three?
sqrt(8)/[2*sqrt(3)] = 2*sqrt(2)/[2*sqrt(3)] = sqrt(2)/sqrt(3) = sqrt(2/3)
How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
How do you simplify the square root of 12 divided by 2?
6
If costheta equals frac2sqrt6 in Quadrant 1 then find tantheta?
tan theta = sqrt(2)/2 = 1/sqrt(2).
What number multiplied by itself equals 72?
To find the number that, when multiplied by itself, equals 72, you need to find the square root of 72. The square root of 72 is approximately 8.49. Therefore, the number that, when multiplied by itself, equals 72 is 8.49.
Is sqrt 2 plus sqrt 2 equals 4?
No
How can you find the area of a hexagon if you already have the perimeter?
A regular hexagon can be divided into 6 equilateral triangles. If a side equals S, then altitude equals S*sqrt(3)/2, and area of that triangle is (S2)*sqrt(3)/4. So the whole hexagon area is 6*(S2)*sqrt(3)/4 = 3*(S2)*sqrt(3)/2. Since S = perimeter/6, then you have: Area = Perimeter2*sqrt(3)/24.
What is the square root of eight divided by 2 square root of three?
sqrt(8)/[2*sqrt(3)] = 2*sqrt(2)/[2*sqrt(3)] = sqrt(2)/sqrt(3) = sqrt(2/3)
How do you do sqrt 8 divided by 28?
0.2857
A plus b equals 4 and ab equals 2 then a4 plus b4 equals?
1 ------ a+b=4 2 ------ ab=2 ====> 3. b = 2/a Sub 3 into 1 ===> a + 2/a = 4 mutiply both sides by a ===> a2 +2 -4a = 0 use quadratic formula to find a ==> a= 2 +sqrt(2) or a' = 2- sqrt(2) use these two values of a to find a value for b using equation 3 ===> using a, b= 2-sqrt(2) and using a', b= 2+sqrt(2) hence a4 + b4 = (2+sqrt(2))4 + (2-sqrt(2))4 = 136 (for both values of a and b)
What is the square root of 98 divided by the square root of 2?
49
Square root of 98 divided by square root of 2?
49
If hx equals f o g x and hx equals sqrt x plus 5 find gx if fx equals sqrt x plus 2?
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
