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If you mean y = -1x +14 then it is a sraight line graph whereas -1 is the slope and 14 is the y intercept

Q: How do you graph m equals -1 b equals 14?

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1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1

It is a straight line with gradient -A/B and intercept C/B.

6b-14=-7-b 6b+b =-7+14 7b =7 b =1

Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.

If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A

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1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1

It is a straight line with gradient -A/B and intercept C/B.

6b-14=-7-b 6b+b =-7+14 7b =7 b =1

Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.

If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A

a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19

y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7

So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.

A straight horizontal line with no slope

ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).

1/a = 1/b: cross multiplying gives a = b

Yes because if 1+0=1 than 0 plus b equals b