1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1
It is a straight line with gradient -A/B and intercept C/B.
6b-14=-7-b 6b+b =-7+14 7b =7 b =1
Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
1-6b+7=14 8-6b =14 -6b =6 -b =1 b =-1
It is a straight line with gradient -A/B and intercept C/B.
6b-14=-7-b 6b+b =-7+14 7b =7 b =1
Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
If B=0, then the graph does not depend on the value of y. This is a vertical line at x = C/A
a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
A straight horizontal line with no slope
ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).
1/a = 1/b: cross multiplying gives a = b
Yes because if 1+0=1 than 0 plus b equals b