33 desks can be arranged into six rows having no rows, 1 row, 2 rows, 3 rows, 4 rows, or 5 rows with exactly 5 desks.
Having the same number of students in each row, 80 students can be arranged in 80 rows of 1, 40 rows of 2, 20 rows of 4, 10 rows of 8, and 5 rows of 16.
If I am getting what you are saying, then no. 3 rows of 9 and 2 rows equals 5 rows. 5*9=45 and 7*9=63
by 2 rows
5
Make an X with 5 pennies. Put hte 6th pennies on top of the center penny.
This is only possible if you allow adding coinsNumber of coins in row x Number of rows = total number of coins5 x 2 = 10 coins4 x 4 = 20 coinsYou would need 10 more coins
1 row of 180 - 2 rows of 90 - 3 rows of 60 - 4 rows of 45 - 5 rows of 36 - 6 rows of 30 - 9 rows of 20 - 10 rows of 18 - 12 rows of 15 - 15 rows of 12 - 18 rows of 10 - 20 rows of 9 - 30 rows of 6 - 36 rows of 5 - 45 rows of 4 - 60 rows of 3 - 90 rows of 2 - 180 rows of 1 - total of 18 ways within the limits of the question
Six ways. 15 rows of 2 trees 6 rows of 5 trees 3 rows of 10 trees and 2 rows of 15 trees 5 rows of 6 trees 10 rows of 3 trees * * * * * How about 1 row of 30 trees and 30 rows of 1 tree each?
1 row of 100 chairs. 2 rows of 50 chairs. 4 rows of 25 chairs. 5 rows of 20 chairs. 10 rows of 10 chairs. 20 rows of 5 chairs. 25 rows of 4 chairs. 50 rows of 2 chairs. 100 rows of 1 chair. Or you could put them all in one big circle.
5 rows with 14 in each row7 rows with 10 in each row
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.