[square root of (7 X 7)] / 7 equals 1. Multiply that by 7 X 7.
The answer is 7s + 49.
To find how many 7s are in the product of 357 and 49, we first calculate the product: ( 357 \times 49 = 17,493 ). Next, we need to determine how many times 7 divides evenly into 17,493. Dividing, we find that ( 17,493 \div 7 = 2,498.71 ), which means there are 2 complete 7s in the product. Thus, the product contains 2 full 7s.
Expressed algebraically, this would equal 7s - 5.
2
5
Five 7s can go into 35. This is because when you divide 35 by 7, the result is 5 (35 ÷ 7 = 5). Therefore, you can fit five 7s into 35 without exceeding it.
5
7,14,21,28,35
2s2+7s-15 = (2s-3)(s+5) when factored
Thetr are: 40/7 = 5 with a remainder of 5
Exactly 9 of them are.9 of them.
5 out of 49 as a decimal = 0.10204= 5/49 =5 ÷ 49 = 0.1024