64 using 3, 5 and 8
5 + 3 = 8
8 x 8 = 64
(5/5)5 = 1
5 * 5 + 3 - 4 is one way.
no
10 divided 3 + 2 times 4 = 8
(5/5-1)+3+1+4.
5*64/15 = 5*6 + 5*4/15 (using the distributive property of multiplication over addition). = 30 + 4/3 = 30 + 11/3 = 311/3
5+4-3+2
4 x 5 + 6 - 3!
There are 4 options for the hundreds digit (3, 4, 5, or 6), and 4 options for the tens digit (including the possibility of repeating the hundreds digit). Similarly, there are 4 options for the units digit. Therefore, the total number of 3-digit numbers that can be formed using the digits 3, 4, 5, and 6 with repetition allowed is 4 x 4 x 4 = 64.
5
You'll need 64 of them because 64*5 = 320
In fifths 12.4/5 = 64/5 In thirds 2.2/3 = 8/3 Make the lower number same, so 5 x 3 = 15 64/5 = 192/15 8/3 = 40/15 192 - 40 = 152 Answer is 152/15