Best Answer

Sinθ plus cosθ2 plus sinθ-cosθ2 equals 2 does not equal 2. It equals 2sinθ. The cosθ2 terms cancel out and you are left with sinθ + sinθ which is 2sinθ.

User Avatar

Wiki User

2010-03-05 02:16:07
This answer is:
User Avatar
Study guides


20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

See all cards
1504 Reviews

Add your answer:

Earn +20 pts
Q: How do you prove that sinθ plus cosθ2 plus sinθ-cosθ2 equals 2?
Write your answer...
Still have questions?
magnify glass
Related questions

What is the solution to cos2 plus cos2tan2 equals 1?

cos2 + cos2tan2 = cos2 + cos2*sin2/cos2 = cos2 + sin2 which is identically equal to 1. So the solution is all angles.

How does 1-sin squared x times 1 plus tan suared x equals 1?

Use these identities: sin2(x) + cos2(x) = 1, and tan(x) = sin(x)/cos(x) For clarity, the functions are written here without their arguments (the "of x" part). (1 - sin2) = cos2 (1 + tan2) = (1 + sin2/cos2) = (cos2+sin2) / cos2 = 1/cos2 Multiply them: (cos2) times (1/cos2) = 1'QED'

How can you prove that 1 plus 1 equals 3?

You can't it equals 2. You can't it equals 2.

Where is cos2 on a ti-83 plus calculator?

There is not cos2 button on a TI-83 plus. You will need to enter the cosine function and then square it. (Press the x2 button to get the squared function.) To type cos2(90) on a TI-83 plus, for example, type: cos(90)2

Can you mathematically prove 9 plus 10 equals 21?

No you can not prove that 9 +10 = 21.

How do you verify cos2 theta divided by csc2 theta plus cos4 theta equals cos2 theta?

Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x

What does negative sine squared plus cosine squared equal?

To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)

How would you prove 1 plus 1 equals 2?

Using a calculator

How does sec squared x equals 1 plus tan squared x?

Original Equationsec2(x) = 1 + tan2(x)Leave the left side assec2(x) and for the proof, try to make the right side equal the left side.We know tan = sin/cos1 + tan2(x) = 1 + sin2(x)/cos2(x)Rewrite the 1 in terms of cos2(x)1 + sin2(x)/cos2(x) = cos2(x)/cos2(x) + sin2(x)/cos2(x)Simplify, now that the denominators have the same termscos2(x)/cos2(x) + sin2(x)/cos2(x) = [ cos2(x) + sin2(x) ] / cos2(x)Use the trig. identity: cos2(x) + sin2(x) = 1[ cos2(x) + sin2(x) ] / cos2(x) = 1 / cos2(x)Remember 1/cosine is equal to secant.\1 / cos2(x) = sec2(x)Recall, the left side the equation was: sec2(x)The right side (we just solved for is): sec2(x)sec2(x) = sec2(x)Left side = right side, Q.E.D.

If a plus b plus c not equal to 0 then a divided by b plus c equals b divided by c plus a equals c divided by a plus b prove that a equals b equals c?

Because there is no way to define the divisors, the equations cannot be evaluated.

Diagram of IE plus SE equals PE?

prove PE=IE+SE

Delta H equals delta E plus delta nRT prove?


People also asked