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If x equals 10 and y equals 10 then 9x plus 8y equals?
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
X plus one over x squared plus two?
it equals x1 it equals x1
X plus 3y equals 4 -x plus 2y equals -4?
x=4 y=0
What is 4x plus 3y plus x equals?
5x+3y
What is -3y plus y equals to?
it is equal to 6y plus y
Do the equations sine plus cosine and sine squared plus cosine squared both equal 1?
No, they do not.
What is cosine squared theta equal to'?
Cosine squared theta = 1 + Sine squared theta
Show that sin ²A plus Cos ²A equals 1?
One definition of sine and cosine is with a unitary circle. In this case, the sine is simply equal to the y-coordinate, and the cosine, the x-coordinate. Since the hypothenuse is 1, the equation in the question follows directly from Pythagoras' Law: x2 + y2 = r2, x2 + y2 = 1, cos2A + sin2A = 1. You can also derive it from the alternative definition of sine and cosine (ratios in a right triangle).
What is the exact value of cosine of pie over 6 plus sine of pie over 3?
dhasdhdsad
CosA equals a2 plus c2 minus b2 by 2ac what is this formula?
This is known as the Cosine Rule.
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
What are the zeros in sine and cosine function?
A "zero of a function" is a point where the dependent value (usually, Y) is zero. In the function f(x) = x2 - 2, for example, there are zeroes at -1.414 and +1.414.The zeroes of the sine function are at all integer multiples of pi, i.e. 0, pi, 2pi, 3pi, etc. The zeroes of the cosine function are at the same points plus pi/2, i.e. pi/2, 3pi/2, 5pi/2, etc.Another way to look at this is that the zeroes of sine are the even multiples of pi/2, and the zeros of cosine are the odd multiples of pi/2.
Solve sin3x plus cos3x equals 6?
If you want sin(3x) + cos(3x) = 6, then this is impossible. Sine and cosine will only return values between -1 and 1, so the expression sin(3x) + cos(3x) could only take values from -2 to 2, although even this is to great as sine and cosine of the same number will never both be 1 or -1. Similarly, if you want a solution to sin3x + cos3x = 6, then this is also impossible, because any power of a number between -1 and 1 will itself be between -1 and 1.
Cos x equals -cos x plus 1?
No, but cos(-x) = cos(x), because the cosine function is an even function.
How do you solve 5SecX plus 3CosecX equals 0 with a Range 0 To 360 Degrees?
Well, let's see.secant = 1/cosinecosecant = 1/sine5/cosine + 3/sine = 0Multiply both sides of the equation by sine :5 sin/cos + 3 = 0But sin/cos = tangent .5 tan(x) + 3 = 05 tan(x) = -3tan(x) = -0.6'x' is the angle whose tangent is -0.6 .
Cosine 35 degrees sine 55 degrees plus sine 35 degrees cosine 55 degreees?
cos(35)sin(55)+sin(35)cos(55) If we rewrite this switching the first and second terms we get: sin(35)cos(55)+cos(35)sin(55) which is a more common form of the sin sum and difference formulas. Thus this is equal to sin(90) and sin(90)=1
How can you solve 1 plus cosx equals sinx?
1 + cos(x) = sin(x)==> You need to find an angle whose sine is 1 greater than its cosine.The numerical values of both the sine and cosine functions range from -1 to +1.No angle has a sin or cosine less than -1 or greater than +1. That'll help us putsome constraints on the equation, and see what may be going on.The equation also says: sin(x) - cos(x) = 1This would be a great place to flash a sketch of the graphs of the sin(x) and cos(x)functions up on the screen, and see where they differ by roughly 1, with the sinebeing the greater one. It's too bad that we can't do that. The best we can do is todraw them on our scratch pad here, look at them, and tell you what we see:-- The sine is greater than the cosine only between 45° and 225°,so any solutions must be in that range of angles.-- At 90°, the sine is 1 and the cosine is zero, so we have [ 1 + 0 = 1 ], and 90° definitely works.-- At 180°, the sine is zero and the cosine is -1, we have [ 1 + -1 = 0 ], and 180° works.-- If there were any range between 45° and 225° where the graphs of the sineand cosine functions were parallel curves, then any angle in that range mightalso be a solution.But there isn't any such place. 90° and 180° are the only points where the valuesare different by 1 and the sine is greater, so those are the only principle solutions(answers between zero and 360°.)
