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Q: How do you represent -123 in twos complement in 10 bit registers?
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How do you represent -123 in twos complement in 10 bits register?

-123 = 11 1000 0101 [I presume the number 123 is in decimal] First write the positive number in binary using 10 bits (I've split it into groups of 4 bits to make it easier to read): 123 = 00 0111 1011 Convert to 1s complement by inverting all bits (any 0 => 1, any 1 => 0): 00 0111 1011 => 11 1000 0100 Finally add 1 to get 2s complement: 11 1000 0100 + 1 = 11 1000 0101 Thus the 2s complement of the negative number: -123 = 11 1000 0101 This can also be expressed in hexadecimal: -123 = 0x385 Or in octal (easy to convert if the binary number is first written in groups of 3 bits): -123 = 1 110 000 101 = 01605 [I've used C notation for the hexadecimal and octal numbers.]


Find the 3's complement of the number 123?

321


What is complement of 123 degree angle?

327 degrees (or -33 deg).


What is the complement of a 57 degree angle?

The complement of an angle is 90 degrees minus the angle 90-57 = 33 degrees


How do you calculate 2s complement of an integer?

Two's complement is the normal implementation of signed integers, so just take the negative. int a = 123; int b = -a; /* b now equals -123 */ The actual implementation of two's complement notation is that, to make something negative, simply invert the bits and then add 1. 12310 = 00000000011110112 (using 16 bit notation) Invert and you get 111111111000100. Add one and you get 111111111000101, so... -12310 = 1111111110001012


How much larger is the supplement of a 57 degree angle than the complement of a 75 degree angle?

The supplementary angle of 57 degrees is 123 degrees The complementary angle of 75 degrees is 15 degrees So: 123 minus 15 = 108 degrees


What is 123 plus 123 equal?

It is: 123+123 = 246


How do you change 123 to a fraction?

You can change it from 123 to 123/1. This is just how to write it on the computer usually. Otherwise, it will be: 123 1


What are three consecutive odd integers that have a sum of 123?

39, 41, 43 Let x represent the smallest of these numbers. From the problem, we know x+(x+2)+(x+4)=123 Solving for x: 3x+6=123 3x=117 x=117/3=39 So our integers are: 39, 41, 43


What is 123 and 123?

123 + 123 = 246 poo faces


What times what equals 123 three times?

Set the cubic root of 123, and we have: ∛123 = ∛(3 * 41) 123 doesn't have the perfect cubic factor, so we express the result as ∛123. If you multiply ∛123 by itself twice, then we have... ∛123 * ∛123 * ∛123 = 123!


How do you turn the ratio 123 into a fraction?

It is 123/1.123, as a fraction is 123/1.