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Two's complement is the normal implementation of signed integers, so just take the negative.

int a = 123;

int b = -a; /* b now equals -123 */

The actual implementation of two's complement notation is that, to make something negative, simply invert the bits and then add 1.

12310 = 00000000011110112 (using 16 bit notation)

Invert and you get 111111111000100. Add one and you get 111111111000101, so...

-12310 = 1111111110001012

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Q: How do you calculate 2s complement of an integer?
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What is the binary complement 8 bit representation for negative 19?

8-bit 2s complement representation of -19 is 11101101 For 1s complement invert all the bits. For 2s complement add 1 to the 1s complement: With 8-bits: 19 � 0001 0011 1s � 1110 1100 2s � 1110 1100 + 1 = 1110 1101


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To get the 2s complement, change all 1 bits to 0s and all 0 bits to 1s, and add 1 to the result. So the 2s complement of the 8-bit binary number 10001011 is the binary integer 01110101. If you want that in decimal, then remember that each place value column is twice the value of the place value column to its right, and the rightmost place value column for an integer is 1. Thus 01110101 in decimal is 64 + 32 + 16 + 4 + 1 = 117 (And 10001011 as a signed 8-bit binary integer represents the decimal integer -117.)


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What is the largest positive number that can be stored using 8 bits?

An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.


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