Well, let's think about this together. To find the 3's complement of a number, we first find the 1's complement by flipping all the bits. So, the 1's complement of 123 would be 876. Then, we add 1 to the 1's complement to get the 2's complement, which is 877. Finally, we add 1 to the 2's complement to get the 3's complement, which is 878. Just remember, mistakes are just happy accidents in the world of math!
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4 3s = 4*3 = 12, which is a rational number.
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
There are no instances of the digit 3 in the number 16. The number 16 consists of the digits 1 and 6. If we were to break down the number 16 into its individual digits, we would have 1 and 6, with no 3 present.
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!