4 3s = 4*3 = 12, which is a rational number.
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
There are no instances of the digit 3 in the number 16. The number 16 consists of the digits 1 and 6. If we were to break down the number 16 into its individual digits, we would have 1 and 6, with no 3 present.
28 3s
L + S = 72 so L = 72 - S; 4L - 3S = 78 ie 4(72 - S) - 3S = 78 ie 288 - 4S - 3S = 78 ie 7S = 210 so S = 30 and L = 42. And there you have it!
123 does not belong because it isn't in the 3s multiplication 31 does not belong because it isn't in the 3s multilplication
4 3s = 4*3 = 12, which is a rational number.
L = S + 11; 2S + 3(S + 11) = 123, ie 2S + 3S + 33 = 123ie 5S = 90 ie S = 18 and L = 29
333,333,333,333,333 trillion
203
They're both the same number.
5 of them with a remainder of 1
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
your browning with the prefix 3s indicates it was made in 1963.
2
The answer depends on which of the two 3s in the number you are referring to!
A 3s orbital is associated with more energy than a 2s orbital. This is because the principal quantum number (n) is higher for the 3s orbital compared to the 2s orbital, resulting in higher energy levels.