i dont now
There is no solution.Consecutive negative integers will always add up to a negative number. 110 is positive.
No two consecutive integers can add up to 98.No three consecutive integers can add up to 98.But 23, 24, 25, and 26 can.
n(n+2)(n+4) = 24
There are no such integers. Proof: choose any positive whole number x two consecutive even integers: (2x) (2x+2) Take the sum (2x)+(2x+2) (2x)+(2x+2)=340 4x+2=340 4x=338 x=338/4=84.5 Since this is not a whole number, there is no whole number that satisfies the conditions. (There are two consecutive odd integers which add up to 340: 169 and 171)
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
10 12 14 are the consecutive even integers which add up to 36
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
The integers are -11, -9 and -7.
The sum of the first 60 positive integers (1 + 2 + 3 + .... + 59 + 60) is equal to 1830.
Let's call the three consecutive integers x, x+1, and x+2. The sum of these integers is x + (x+1) + (x+2) = 3x + 3. We know that this sum is equal to 135, so we can set up the equation 3x + 3 = 135. Solving for x gives us x = 44. Therefore, the three consecutive integers are 44, 45, and 46.
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
The pair of consecutive integers which add up to 55 are 27 and 28. Therefore, any consecutive pair of numbers below 27 and 28 add up to a total less than 55.