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What three consecutive integers have a sum of 43?
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
Find two consecutive negative odd integers whose product is 399?
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
Find two consecutive negative integers whose product is 90?
-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.
How do you find three consecutive even integers is 318?
To find three consecutive even integers that sum to 318, let the first integer be ( x ). The next two consecutive even integers would then be ( x + 2 ) and ( x + 4 ). Setting up the equation, we have ( x + (x + 2) + (x + 4) = 318 ). Simplifying this gives ( 3x + 6 = 318 ), or ( 3x = 312 ), leading to ( x = 104 ). Thus, the three consecutive even integers are 104, 106, and 108.
Find two consecutive integers that have a sum of -67?
The integers are -34 and -33.
What are the consecutive odd integers of 152?
find the two consecutive odd integers with a sum of 152
What three consecutive integers have a sum of 43?
Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.
What is the product of two consecutive integers that equals 132?
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
Find two consecutive negative odd integers whose product is 399?
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
Find two consecutive even integers so that three times the smaller is 40 mor than two time the larger?
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
What is The sum of the squares of two consecutive positive even integers is 340 Find the integers?
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
What is the sum of three consecutive integers is 88?
Let's represent the three consecutive integers as x, x+1, and x+2. To find their sum, we add these integers together: x + (x+1) + (x+2) = 88. Simplifying the equation gives us 3x + 3 = 88. Subtracting 3 from both sides and then dividing by 3, we find that x = 28. Therefore, the three consecutive integers are 28, 29, and 30, and their sum is indeed 88.
The product of three consecutive integers is 9240 find the integers?
9240 is the product of the three consecutive integers 20, 21, and 22.
Find two consecutive negative integers whose product is 90?
-9 or -10Two consecutive negative integers that can be multiplied together with a product of 90 would be -9 and -10. A number sentence for this equation would be: -9 X -10 = 90.
Find four consecutive integers?
1,2,3,4
Find the two consecutive positive integers is 132 find the integers?
The numbers are 65 and 67.
How do you find three consecutive even integers is 318?
To find three consecutive even integers that sum to 318, let the first integer be ( x ). The next two consecutive even integers would then be ( x + 2 ) and ( x + 4 ). Setting up the equation, we have ( x + (x + 2) + (x + 4) = 318 ). Simplifying this gives ( 3x + 6 = 318 ), or ( 3x = 312 ), leading to ( x = 104 ). Thus, the three consecutive even integers are 104, 106, and 108.
