First set up the equation:
2h+10=40
Then get the variable alone by subtracting 10 from each side:
2h=30
And continue by dividing both sides by two
2h=30
______
2 2
h=15
So your answer is h=15
2h + 2h + 2h = 6h
6h 8min
(t+h)(x+2)
When h=10, 2h-9 = 2(10)-9 = 20-9 = 11 .
D=2h h=4000ft D=2(4000 ft) D=8000 ft
3h-5h + 11 = 17 is ------2h + 11 = 17- 11 -11____________-2h = 6___ ___-2 -2h = -3 (This is the answer.)
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
2Si +2HF-2siF + 2H
The complete ionic equation for this reaction is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq)
h = 0.538462 14 + 5h + 2h = 5h + 28h 14 + 7h = 33h 14 + 7h - 7h = 33h - 7h 14 = 26h 14/26 = 26/26h 0..538462 = h
A = 2lw + 2lh + 2wh so A - 2lw = 2lh + 2wh = 2h(l+w) = h*2(l+w) so h = 1/2*(A-2lw)/(l+w)