When h=10, 2h-9 = 2(10)-9 = 20-9 = 11 .
It's hard for us to shake the impression that you're not quite sure ofwhat you're looking for.You're looking for the value of 'h' that will make this statement true.Here's how to find it:10 + 5h = 25Subtract 10 from each side of the equation:5h = 15Divide each side by 5:h = 3
Unless you have a value for 'h', the answer will just be an expression: 10 + 7h
The differences are 400 and 40 respectively
f = 54
84
h - 4 = 10 Therefore, h = 10 + 4 h = 14
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
The H equals 6.626 *10^-34 which is commonly known as Planck's constant.
'H' can have an infinite number of different values, depending on the value of 't' . If you specify a definite numerical value for 't', then the value of 'H' can be calculated.
The value of h is 9
Remember: by definition the concentration of hydrogen ions (in mol/L) is equal to 10 to the negative power of the pH value (pH).[H+] = 10-(pH)Using this we find that: [H+] = 10-1.0 = 0.1 for pH = 1.0 and[H+] = 10-2.0 = 0.01 for pH = 2.0 , thus 10x smaller!
It's hard for us to shake the impression that you're not quite sure ofwhat you're looking for.You're looking for the value of 'h' that will make this statement true.Here's how to find it:10 + 5h = 25Subtract 10 from each side of the equation:5h = 15Divide each side by 5:h = 3
2
r = 60 m/h t = 2 h D = r t = (60m/h) x (2h) = 120 mi
If an aqueous solution has a pOH value of 10.7 and is at standard temperature and pressure, the pH value is 14 - 10.7 = 3.3. From the definition of pH, this means that the logarithm (to base 10) of the molar concentration of H+, [H+] is -3.3. This can be written as +0.7 - 4. The antilog of 0.7 is 5, to the justified number of significant digits. Therefore, [H+] = 5 X 10-4.
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
h= -4