It's hard for us to shake the impression that you're not quite sure ofwhat you're looking for.You're looking for the value of 'h' that will make this statement true.Here's how to find it:10 + 5h = 25Subtract 10 from each side of the equation:5h = 15Divide each side by 5:h = 3
Unless you have a value for 'h', the answer will just be an expression: 10 + 7h
The differences are 400 and 40 respectively
f = 54
84
h - 4 = 10 Therefore, h = 10 + 4 h = 14
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
The H equals 6.626 *10^-34 which is commonly known as Planck's constant.
'H' can have an infinite number of different values, depending on the value of 't' . If you specify a definite numerical value for 't', then the value of 'H' can be calculated.
The value of h is 9
The pH of a solution is calculated using the formula pH = -log[H+]. Plugging in the given value of [H+] = 7.0x10^-7, you would get a pH of 6.15 for this solution.
The pH of a solution can be calculated using the formula pH = -log[H+]. Plugging in the value of [H+] = 2.3 x 10^-4 gives a pH of 3.64.
It's hard for us to shake the impression that you're not quite sure ofwhat you're looking for.You're looking for the value of 'h' that will make this statement true.Here's how to find it:10 + 5h = 25Subtract 10 from each side of the equation:5h = 15Divide each side by 5:h = 3
2
r = 60 m/h t = 2 h D = r t = (60m/h) x (2h) = 120 mi
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
h= -4